Melody

log ₁₂  81 + log ₁₂  256

$$\frac{log81}{log12}+\frac{log256}{log12}\\\\
=\frac{log81+log256}{log12}\\\\$$

$${\frac{\left({log}_{10}\left({\mathtt{81}}\right){\mathtt{\,\small\textbf+\,}}{log}_{10}\left({\mathtt{256}}\right)\right)}{{log}_{10}\left({\mathtt{12}}\right)}} = {\mathtt{3.999\: \!999\: \!999\: \!999\: \!999\: \!7}}$$

I suspect that the exact answer is 4.  So there is probably an exact way to do this.

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I'll think about it.  

$$\begin{array}{rlll}
\frac{cos42}{1}&=&\frac{1000}{x}\qquad&\mbox{ The x needs to be on the top so turn both sides upside down }\\\\
\frac{1}{cos42}}&=&\frac{x}{1000}\qquad&\mbox{ Multiply both sides by 1000}\\\\
1000\times \frac{1}{cos42}}&=&x\qquad&\mbox{ Get the answer with a calculator }\\\\
x&=&1345.6327\qquad&\mbox{ }\\\\
x&=&1346\qquad&\mbox{ To the nearest whole number }\\\\

\end{array}$$

hi MeteorShower and welcome to web2.0calc forum 

My answer might look a bit long but it is worth your while to work through it.  

you have 3010 tickets  and there will be 14 concerts.

Each concert has the same number of tickets.

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Let's think about another easier problem first.

You have 10 lollies and you want to divide them between 5 children.

2+2+2+2+2=2 x 5=10  so they get 2 lollies each.

How can you put 10 and 5 together to get 2?     

10 divided by 5 =2

10 lollies divided between 5 children = 10 ÷ 5 = 2  

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NOW for your problem.

3010 tickets divided between 14 concerts must be 3010÷14=215 tickets for each concert

CHECK

215 x 14 = 3010   That is right.  Excellent!

Okay Dragon slayer,

Put them up (on the forum)  one at a time and try and do them yourself as you go.

I can not tell other people to answer, that is up to them.  

But we are here to help you learn, not to do all your homework for you without you even thinking about it.

thanks chris,

You need to skech a graph of it then it should be clear.

Answer these they are hints for your questions. 

4*4*4=(4)³=

2*2*2*2=2⁴=

3*3*3*3=3⁴=

I'm not sure what this one means 

4 sqrt x20y28

$$4\sqrt{x} \times20\times y^{28}$$      perhaps?

mmm let's think about that.

The vertex is (5,3)

It is a (pos) sideways parabola 8=4*2 so the focal length is 2.

So the focus must be y=3 x=5+2     

focus (7,3)

that sounds right to me.  

$$\begin{array}{rlll}
g(x)-f(x)&=&2x^2-16-[(2x+3)(x-2)]&\\\\
&=&2x^2-16-[(2x(x-2)+3(x-2)]&\\\\
&=&2x^2-16-[2x^2-4x+3x-6]&\\\\
&=&2x^2-16-[2x^2-x-6]&\\\\
&=&2x^2-16-2x^2+x+6&\\\\
&=&x-10&\\\\
\end{array}$$

sqrt(10000/81)=sqrt(10000)/sqrt(81)=100/9=11 and 1/9

$$\frac{\sqrt{64}}{\sqrt{169}}=\frac{8}{13}$$

You can not find the square root of a negative number.