NinjaDevo

Basically the question asker is wanting you to reduce this fraction.

Think what number you could divide both the top and the bottom numbers by to come out with a whole number (not a decimal point. ex: 7.444)

Then, once you get a reduced fraction, see if you can reduce it again by dividing the top and bottom again. If you cannot do this and get a whole number, your fraction is fully reduced!

See if you can solve this question with the information I've just given you.

(12.01) ÷ 6.022*10²³

12.01 is the same thing as 1.201 x 10¹

(1.201 x 10¹) ÷ (6.022 x 10²³)

(1.201 ÷  6.022)(10¹ ÷  10²³)

.1994354 x 10^-22

this is the same as

(1.994354 x 10¹) x 10^-22

1.994354x 10^-21

Round down to 4 significant digits.

1.994 x 10^-21

This method is known as scientific notation. It helps when your dealing with really big or really small numbers. You could also write this as 0.0000000000000000000000199435

3x

By dividing both sides by 3, this can be simplified to:

x<4

This is saying that x could be any number below 4.

x could even be -99999999 for that matter!

The rule for rounding is that if it is 5 or higher, round up. If it is 4 or lower, round down.

But...this depends where your rounding too.

If you wanted to round to the nearest whole number, you would get:

3

If you wanted to round to the tenths place, you would get:

2.9

If you wanted to round to the hundredths place, you would get:

2.90

If you wanted to round to the thousandths place, you would get:

2.897

If you wanted to round to the ten-thousandths place, you would get:

2.8974

To solve this, we need to set up two equations and solve them like you would solving inequalities by elimination.

N + Q = 60          ---This one is telling us that 60 coins are made up of nickles and quarters.

.05N+.25Q = 7.40      ---This one is telling us that the total balance is $7.40 and quarters are worth 25 cents,                                                        and nickles are worth 5 cents.

If we move the decimal place over on all three numbers, we can write the second equation as:

5N+25Q=740

Now, to solve with elimination we need to have 5N in both the equations. Let's multiply everything in the first equation by 5 so we have 5N in both equations.

5(N + Q = 60)

5N+5Q=300

Now, we solve by elimination with our two new equations.

5N+25Q=740

-5N -5Q= -300

20Q=440

Q = 22                    ---Divide both sides by 20

There are twenty-two quarters!

To find how many nickles there are, put in 22 instead of Q for one of the equations (we can do this because Q = 22)

Let's take our original first equation.

N + Q = 60

N + 22 = 60

N = 38                  ---Subtract 22 from both sides

There are 38 nickles!

To check this, let's put in these values of N and Q into our original second equation.
.05N+.25Q = 7.40

.05(38)+.25(22) = 7.40

1.9+5.5 = 7.40

7.4 = 7.4

It works!

To type in a division sign on this calculator, you can click the little ÷ button, or you can type in a backslash which looks like this: /

The reason you use / is because there is no divided by sign on most keyboards, and the / symbol is on almost every keyboard.

#FrozenReference

Much thanks, Sir Dragon.

I shall be wary of thee.

We have a piece of cloth 12 and 1/3 yards long.

Since a 3/4 yard piece can't be cut out of a 1/3 yard-long piece, let's forget about this 1/3 yard piece and just figure out how many 3/4 yard pieces can be cut out of a 12 yard piece.

12/1 ÷ 4/3

To divide two fractions, multiply by the reciprocal.

12/1 x 4/3

48/3

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