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0
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(12.01) /6.022*10²³

 Jun 24, 2014

Best Answer 

 #3
avatar+118723 
+10

Great explanation  Ninja but I think you made an error.

(12.01) ÷ (6.022*1023)  You have assumed the brackets which is not an unreasonable assumption

12.01 is the same thing as 1.201 x 101      

You would have been better off to have left it as 12.01 but it doesn't matter.

(1.201 x 101) ÷ (6.022 x 1023)

(1.201 ÷  6.022)(101 ÷  1023)

.1994354 x 10-22     Good to here

this is the same as

(1.994354 x 10-1) x 10-22        It is 10-1 NOT 10+1

1.994354x 10-23

Round down to 4 significant digits.

1.994 x 10-23

 Jun 24, 2014
 #1
avatar
0

74$${\mathtt{X}}{\mathtt{\,\small\textbf+\,}}{\mathtt{69}}{\mathtt{\,\small\textbf+\,}}{\mathtt{420}} = {\mathtt{489}}{\mathtt{\,\small\textbf+\,}}\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{X}}}$$

 Jun 24, 2014
 #2
avatar+3454 
+5

(12.01) ÷ 6.022*1023

12.01 is the same thing as 1.201 x 101

(1.201 x 101) ÷ (6.022 x 1023)

(1.201 ÷  6.022)(101 ÷  1023)

.1994354 x 10-22

this is the same as

(1.994354 x 101) x 10-22

1.994354x 10-21

Round down to 4 significant digits.

1.994 x 10-21

This method is known as scientific notation. It helps when your dealing with really big or really small numbers. You could also write this as 0.0000000000000000000000199435

 Jun 24, 2014
 #3
avatar+118723 
+10
Best Answer

Great explanation  Ninja but I think you made an error.

(12.01) ÷ (6.022*1023)  You have assumed the brackets which is not an unreasonable assumption

12.01 is the same thing as 1.201 x 101      

You would have been better off to have left it as 12.01 but it doesn't matter.

(1.201 x 101) ÷ (6.022 x 1023)

(1.201 ÷  6.022)(101 ÷  1023)

.1994354 x 10-22     Good to here

this is the same as

(1.994354 x 10-1) x 10-22        It is 10-1 NOT 10+1

1.994354x 10-23

Round down to 4 significant digits.

1.994 x 10-23

Melody Jun 24, 2014

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