shaniab29544

-48+9(x4−4x)=6(12−x)+9x4-48+9x4−36x=72−6x+9x4-48+9x4=72+30x+9x4-120+9x4=30x+9x4-120=30x-4=x

thank u

If you have the equation of a parabola in vertex form y = a(x - h)² + k, then the vertex is at (h, k) and the focus is (h, k + 1/(4a)). Notice that here we are working with a parabola with a vertical axis of symmetry, so the x-coordinate of the focus is the same as the x-coordinate of the vertex

2-3=-1

3/4+6/2+(-9/4) equal to 1.5 or as 1 1/2

2/9 divded by 4/5 plus 563/6000 equal to 0.372611111 so it must me be 0.37

so my first answer is right awsome

3250-1980*1000/1502250=3248.68

to brEAK DOWN:3250-1980=1270*1000=1270000/1502250=0.8

it one of the answer 

and melody please corret me this person

ok than the first answer thank u

Since more than half of each row of cups must contain beans, each row will need at least five beans. This means that at least two of the empty cups in the first row and at least four of the empty cups in the second row must have beans added to them.

For the game operator to have the advantage over the player, the probability that the two cups selected will both contain beans must be less than 50%. The probability that the cups will both contain beans is the product of the probabilities of the cup from each row containing a bean. Adding beans to two of the empty cups in the first row and four of the empty cups in the second row will result in the probability that both cups selected contain beans being 58⋅58=2564≈39.06%, which is less than 50%.

 Add beans to two of the empty cups in the first row and four of the empty cups in the second row.