+961 The quadratic equation y=-(x+6)2+13 is given.
Identify the coordinates of the vertex.
( , )
What is the maximum value?
+961 The equation y=-(x+6)2+13 is given in vertex form, y=a(x−h)2+k.
So the vertex is ( - 6, 13 ) since h=−6 and k=13.
Since a is negative, the function opens downward and would therefore have a maximum . The maximum value is 13.
+128475 y=-(x+6)2+13 ...since this is in the form, y = a(x - h)2 + k, the vertex is at (h, k) i.e, (-6,13)
And the minus sign out front means that this parobola turns "downward," .....so, the vertex is always the maximum value whenever that's the case...
+961 The equation y=-(x+6)2+13 is given in vertex form, y=a(x−h)2+k.
So the vertex is ( - 6, 13 ) since h=−6 and k=13.
Since a is negative, the function opens downward and would therefore have a maximum . The maximum value is 13.
