The quadratic equation y=-(x+6)2+13 is given.
Identify the coordinates of the vertex.
( , )
What is the maximum value?
y=-(x+6)2+13 ...since this is in the form, y = a(x - h)2 + k, the vertex is at (h, k) i.e, (-6,13)
And the minus sign out front means that this parobola turns "downward," .....so, the vertex is always the maximum value whenever that's the case...