The quadratic equation y=-(x+6)2+13 is given.

Identify the coordinates of the vertex.

( , )

What is the maximum value?

shaniab29544 Jan 7, 2015

#4**+10 **

The equation y=-(x+6)2+13 is given in vertex form, y=a(x−h)2+k.

So the vertex is ( - 6, 13 ) since h=−6 and k=13.

Since *a* is negative, the function opens downward and would therefore have a maximum . The maximum value is 13.

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shaniab29544 Jan 7, 2015

#1**+5 **

y=-(x+6)^{2}+13 ...since this is in the form, y = a(x - h)^{2} + k, the vertex is at (h, k) i.e, (-6,13)

And the minus sign out front means that this parobola turns "downward," .....so, the vertex is always the maximum value whenever that's the case...

CPhill Jan 7, 2015

#4**+10 **

Best Answer

The equation y=-(x+6)2+13 is given in vertex form, y=a(x−h)2+k.

So the vertex is ( - 6, 13 ) since h=−6 and k=13.

Since *a* is negative, the function opens downward and would therefore have a maximum . The maximum value is 13.

** **

shaniab29544 Jan 7, 2015