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The quadratic equation y=-(x+6)2+13 is given.

Identify the coordinates of the vertex.

(  ,  )

What is the maximum value?

 

 Jan 7, 2015

Best Answer 

 #4
avatar+961 
+10

The equation y=-(x+6)2+13 is given in vertex form, y=a(xh)2+k.

So the vertex is ( - 6, 13 ) since h=6 and k=13.

Since a is negative, the function opens downward and would therefore have a maximum . The maximum value is 13.

 

 Jan 7, 2015
 #1
avatar+101872 
+5

y=-(x+6)2+13   ...since this is in the form, y = a(x - h)2 + k, the vertex is at (h, k) i.e, (-6,13)

And the minus sign out front means that this parobola turns "downward," .....so, the vertex is always the maximum value whenever that's the case...

 

 Jan 7, 2015
 #2
avatar+961 
0

thank u

 Jan 7, 2015
 #3
avatar+101872 
0

OK, shaniab.....!!!

 

 Jan 7, 2015
 #4
avatar+961 
+10
Best Answer

The equation y=-(x+6)2+13 is given in vertex form, y=a(xh)2+k.

So the vertex is ( - 6, 13 ) since h=6 and k=13.

Since a is negative, the function opens downward and would therefore have a maximum . The maximum value is 13.

 

shaniab29544 Jan 7, 2015

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