What is the solution to the equation 7(x3+3x−1)=17x+7(x3+11)?
x= to the third power
7(x3 + 3x -1) = 17x + 7(x3 + 11)
7x3 + 21x - 7 = 17x + 7x3 + 77
Subtract 7x3 from both sides
21x - 7 = 17x + 77
Subtract 17x from both sides
4x - 7 = 77
Add 7 to both sides
4x = 84
Divide both sides by 4
x = 21
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Thank you