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What is the solution to the equation 7(x3+3x1)=17x+7(x3+11)?

x= to the third power 

 Apr 21, 2015

Best Answer 

 #1
avatar+30372 
+10

7(x3 + 3x -1) = 17x + 7(x3 + 11)

 

7x3 + 21x - 7 = 17x + 7x3 + 77

 

Subtract 7x3 from both sides

21x - 7 = 17x + 77

 

Subtract 17x from both sides

4x - 7 = 77

 

Add 7 to both sides

4x = 84

 

Divide both sides by 4

x = 21

.

 Apr 21, 2015
 #1
avatar+30372 
+10
Best Answer

7(x3 + 3x -1) = 17x + 7(x3 + 11)

 

7x3 + 21x - 7 = 17x + 7x3 + 77

 

Subtract 7x3 from both sides

21x - 7 = 17x + 77

 

Subtract 17x from both sides

4x - 7 = 77

 

Add 7 to both sides

4x = 84

 

Divide both sides by 4

x = 21

.

Alan Apr 21, 2015
 #2
avatar+961 
+5

Thank  you 

 Apr 22, 2015

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