What is the solution to the equation 7(x3+3x−1)=17x+7(x3+11)?

x= to the third power

7(x^{3} + 3x -1) = 17x + 7(x^{3} + 11)

7x^{3} + 21x - 7 = 17x + 7x^{3} + 77

Subtract 7x^{3} from both sides

21x - 7 = 17x + 77

Subtract 17x from both sides

4x - 7 = 77

Add 7 to both sides

4x = 84

Divide both sides by 4

x = 21

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Thank you