supermanaccz

Click on the link to read Melody’s and CHilll’s solutions. 

Very beautiful question with an elegant solution! :)

Hello! I believe this question is already answered here:

https://web2.0calc.com/questions/let-abc-be-any-triangle-equilateral-triangles-bcx 

A joke thread would be nice too!

Same for me probably. 

Worst is definitely when my close relatives die, e.g. (grandparents, parents, etc.)

Best is probably when I successfully start my own company?

may you please type out the second part, I cannot read it :)

Alright, here we go:

In n/m, both are relatively prime and cannot simplify the fraction. 

To prove that √3 is irrational from n^2 = 3m^2

From n^2 = 3m^2, we can say that n is a multiple of 3, since there is a 3 on the right side of the equation. 

We can set n equal to 3k

So n^2 = 9k^2 = 3m^2

3k^3 = m^2

So this means that m is also a multiple of 3.

In the beginning we stated that they are relatively prime and cannot simplify, but if both are n and m are multiples of 3, how is this possible?

This leads to a contradiction. 

This may be right if there were no restrictions, but as I stated in the problem, you must be able to circle to letters R-S-M going left to right without anything in between. 

The last few example were not correct because R-S-M are not in that order next to one another. 

Thanks for trying!

Here’s what google says:

A compound translation is a transformation that encapsulates a sequence of transformations so that when the compound transformation is applied to an object the entire sequence of constituent transformations are applied and then the new object is displayed.

How are we supposed to use pi in the problem. And what do we do?

The answer is the second choice. 

This is the standard form of a circle, so it must be the second choice.