+0  
 
0
40
2
avatar

 

Hello! I have a friend who needs some help getting this problem. I'm afriad I am a little unavailable to help currently, so I had to come to you guys, since I know you are the best! Any help or info that can be provided is greatly appreciated. I sincerely thank you all for all that you do and all the time you deticate to helping us all. Have a nice day and thank you in advance!

 

 

Guest Mar 21, 2018
Sort: 

2+0 Answers

 #1
avatar+560 
+1

Alright, here we go:

 

In n/m, both are relatively prime and cannot simplify the fraction. 

 

To prove that √3 is irrational from n^2 = 3m^2

 

From n^2 = 3m^2, we can say that n is a multiple of 3, since there is a 3 on the right side of the equation. 

 

We can set n equal to 3k

 

So n^2 = 9k^2 = 3m^2

 

3k^3 = m^2

 

So this means that m is also a multiple of 3.

 

In the beginning we stated that they are relatively prime and cannot simplify, but if both are n and m are multiples of 3, how is this possible?

 

This leads to a contradiction. 

supermanaccz  Mar 21, 2018
 #2
avatar+560 
0

may you please type out the second part, I cannot read it :)

supermanaccz  Mar 21, 2018

11 Online Users

avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details