tertre

The exponential growth formula states that a(1+r)^t, where a is the initial amount, r is the ratio, t is the time.

Filling in the values, we have 740(1+0.09)^8=740(1.09)^8=1474.50.

Notice that 3*5=15 and 3*7=21, thus the side lengths are 3 units, 5 units, and 7 units. The total volume is therefore 3*5*7=105 square units.

The axis of symmetry can be found by using -b / 2a.

y=-x^2-6x-7..

-(-6) / 2(-1)= 6/-2=-3- which is the axis of symmetry.

Put x=-3 back into the equation...

y=-(-3)^2-6(-3)-7=2.

Thus, the vertex is (-3,2).

Posted twice by accident...

Notice that AC splits the quadrilateral into two pieces.

ABC is a triangle as well as ADC.

By the Triangle Inequality for triangle ABC, AC must be greater than 6-3=3 and less than 6+3=9. The values are between 4 and 8, inclusive.

By the Triangle Inequaliyt for triangle ADC, AC must be greater than 4-4=0 and less than 4+4=8. The values are between 1 and 7, inclusive.

Thus, the values in the intersection between the two inequalities are from 4-7 for 7-4+1=4 values that satisfy AC, namely 4, 5, 6, and 7 units.

Parallel line to 4y-12x=11 means it has the same slope as that line.

4y=12x+11

y=3x+11/4

y=3x+b

6=-6+b

b=12

y=3x+12

Based in the question, it is to see that point Z is the midpoint of line XY.

(x+1) / 2 = -1    x+1=-2,  x=-3

(y+7) / 2 = -7,  y+7=-14,  y=-21

(-3,-21)

It's better to remember the unit circle for this one...

pi / 3 + 2pi (n) 

5pi/3  + 2pi(n)

1/a + 1/b = 2/17

b/ab+a/ab=2/17

a+b/ab=2/17

17(a+b)=2ab

17a+17b=2ab

2ab-17a-17b=0

Multiply the equation by two...

4ab-34a-34b=0

If 289(17^2) is added to both sides, then (2a-17)(2b-17)=289.

289=1*289 and 17*17.

2a-17=1  

2a=18   a=9              2b-17=289   2b=153             (9,153), (153,9)

2a-17=17  2a=34  a=17            2b-17=17,  2b=34, b=17            (17,17)

Thus, there should be three(3) positive ordered pairs.

A median bisects the side in half(1/2).

Let the side AC=2a and CB=2B, thus, the medians divide the sides into a and b, respectively.

Systems of equations gives us...

a^2+(2b)^2=(13)^2

(2a)^2+b^2=(19)^2

a^2+4b^2=169

4a^2+b^2=361

Solve for 2a, and 2b 2\sqrt 85 and b=2\sqrt21

c^2=424 ...solve for c

probably made a mistake somewheree !

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