Thanks, CPhill!

Good job, RainbowPanda!

x is not 5.....

First, we can apply the radical rule, to get \(\sqrt{-1}\sqrt{9}\) . Then we can apply the imaginary rule, to get \(\sqrt{9} i=3i\) . Doing the same thing with, \(\sqrt{-36}\), we get \(6i\) . So, \(3i+6i=\boxed{9i}\)

Hey, Manuel!

We can first subtract \(-8+y\) from both sides, to get \(\sqrt{y^2}-8+y-(-8+y)=4-(-8+y), \sqrt{y^2}=-y+12\). After that, we can square both sides, expand, and expand again, to get \(y^2=y^2-24y+144\) . Solve, to get \(y=6\)

That is correct, EP and GA! Good job, both of you!

Beautiful explanation, CPhill! I like it!

Using the forumla, 4/3 pi r^3, we have 4/3*3.14*216=904.32cm^3, so the third option.

CPhill?????????????/

Great job, CPhil! Amazing Explanation!

Thanks, EP! Great Explanation!

Amazing Explanation, CPhill! Great job!

Great diagram! Thanks so much, EP!

That is correct! Good job, hectictar! Amazing!