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y = -x^2 - 6x - 7
what is the axis of symmetry and vertex?

 Apr 10, 2020

Best Answer 

 #1
avatar+4569 
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The axis of symmetry can be found by using -b / 2a.

y=-x^2-6x-7..

 

-(-6) / 2(-1)= 6/-2=-3- which is the axis of symmetry.

 

 

Put x=-3 back into the equation...

 

y=-(-3)^2-6(-3)-7=2.

 

 

Thus, the vertex is (-3,2).

 Apr 10, 2020
 #1
avatar+4569 
+1
Best Answer

The axis of symmetry can be found by using -b / 2a.

y=-x^2-6x-7..

 

-(-6) / 2(-1)= 6/-2=-3- which is the axis of symmetry.

 

 

Put x=-3 back into the equation...

 

y=-(-3)^2-6(-3)-7=2.

 

 

Thus, the vertex is (-3,2).

tertre Apr 10, 2020

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