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Question from my book: Find the length of the side of the rhombus which has area 40 and diagonals with length 2x and 3x-2. 

My answer: square root of 41...Is this correct?

Well, first the area for solving the area of the rhombus is: \(d_1d_2/2\),  so (2x)(3x-2)=80.

Then, take 80 to the other side, solve the quadratic and get the roots x=4, x=-10/3. Since x has to be positive, so the diagonals have length 2(4)=8 and 3(4)-2=10. We are looking for the side length, so is it square root of 4^2+5^2, since the diagonals are 8 and 10...Therefore, the answer is \(\sqrt{41}\)

 

Sorry for my bad latex. Is it correct? Thanks!

 Sep 25, 2018
 #1
avatar+4424 
+2

You are correct.

 Sep 26, 2018
 #2
avatar+98107 
+1

Nice work, tertre....!!!

 

 

cool cool cool

 Sep 26, 2018
 #3
avatar+3994 
+1

Thank you, Rom and CPhill!

 Sep 27, 2018

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