+4622 In the diagram below, \(\overline{AB}\parallel \overline{CD}\) and \(\angle AXE\) is \(108^\circ\) less than 3 times \(\angle CYX\). Find \(\angle BXY\).
+983 Hi tertre,
Since line AB is parallel to line CD, angle AXE is equal to CYX.
This means we can set angle AXE = angle CYX = x
Since AXE is 108º less than 3 times CYX, we have this:
\(x+108=3x\)
Solving for x, we get:
\(x=54\)
We know that AXE and CYX = 54º
Since AXE and BXY are congruent angles, we know that
\(BXY=54º\)
I hope this helps,
Gavin
+983 Hi tertre,
Since line AB is parallel to line CD, angle AXE is equal to CYX.
This means we can set angle AXE = angle CYX = x
Since AXE is 108º less than 3 times CYX, we have this:
\(x+108=3x\)
Solving for x, we get:
\(x=54\)
We know that AXE and CYX = 54º
Since AXE and BXY are congruent angles, we know that
\(BXY=54º\)
I hope this helps,
Gavin
