+0  
 
+1
223
2
avatar+3276 

In the diagram below, \(\overline{AB}\parallel \overline{CD}\)  and \(\angle AXE\) is \(108^\circ\) less than 3 times \(\angle CYX\). Find \(\angle BXY\).

 

tertre  Apr 21, 2018

Best Answer 

 #1
avatar+963 
+5

Hi tertre,

 

Since line AB is parallel to line CD, angle AXE is equal to CYX.

 

This means we can set angle AXE = angle CYX = x

 

Since AXE is 108º less than 3 times CYX, we have this:

 

\(x+108=3x\)

 

Solving for x, we get:

 

\(x=54\)

 

We know that AXE and CYX = 54º

 

Since AXE and BXY are congruent angles, we know that

 

\(BXY=54º\)

 

I hope this helps, 

 

Gavin

GYanggg  Apr 21, 2018
 #1
avatar+963 
+5
Best Answer

Hi tertre,

 

Since line AB is parallel to line CD, angle AXE is equal to CYX.

 

This means we can set angle AXE = angle CYX = x

 

Since AXE is 108º less than 3 times CYX, we have this:

 

\(x+108=3x\)

 

Solving for x, we get:

 

\(x=54\)

 

We know that AXE and CYX = 54º

 

Since AXE and BXY are congruent angles, we know that

 

\(BXY=54º\)

 

I hope this helps, 

 

Gavin

GYanggg  Apr 21, 2018
 #2
avatar+3276 
+2

Thanks for the detailed explanation, Gavin! smileysmiley

tertre  Apr 21, 2018

12 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.