Yes, they are also called complementary angles.
This is just: \(3\frac{2}{10}=\boxed{3{\frac{1}{5}}}\) .
Since we have a line segment, this attains \(a+2x+3x=80\). Now, plugging in the value of \(a\), we get \(45+5x=180, 5x=135\) . Solving for \(x\), we get \(\boxed{x=27^\circ}.\)
Just count the end results. Since we have two for each, our answer is \(2*2=\boxed{4}.\)
Just multiply: \(\frac{5}{7}*14=5*2=\boxed{10}.\)
Thank you, CPhill! Great solution!
No angle should be less than 61 degrees. This question was also posted here: https://web2.0calc.com/questions/help_53845
Lol! It's okay, I'm watching football, too!
@CPhill, isn't it 5x=100, x=20?
Not quite, Rom. Continuing with my method and plugging the values of b, we get b=6, so the answer is \(\boxed{\frac{5}{6}}.\) Can someone verify this?
