+0  
 
0
338
1
avatar

0.10 = 6.0/v^2 + 0.00050v^2 - 0.033

what is v=?

pls detailed instruction on how to. :)

Guest May 8, 2014

Best Answer 

 #1
avatar+92623 
+8

$$v\ne0$$

$$0.1=\frac{6}{v^2}+0.0005v^2-0.033\\\\
0.133=\frac{6}{v^2}+0.0005v^2\\\\
0.133v^2=6+0.0005v^4\\\\$$

substitute x for v2

$$0.0005x^2-0.133x+6=0\\$$

 

$${\mathtt{0.000\: \!5}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{0.133}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{133}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{5\,689}}}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{5\,689}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{133}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{57.574\: \!540\: \!107\: \!467\: \!690\: \!7}}\\
{\mathtt{x}} = {\mathtt{208.425\: \!459\: \!892\: \!532\: \!309\: \!3}}\\
\end{array} \right\}$$

 

 $$v^2=57.574540\:\:\rightarrow v=\pm7.58779\:\: \mbox{approx}$$   or

$$v^2=208.42545989\:\:\rightarrow\:\:v=\pm14.4369\:\:\mbox{approx}$$

I think that is all okay.

Melody  May 8, 2014
 #1
avatar+92623 
+8
Best Answer

$$v\ne0$$

$$0.1=\frac{6}{v^2}+0.0005v^2-0.033\\\\
0.133=\frac{6}{v^2}+0.0005v^2\\\\
0.133v^2=6+0.0005v^4\\\\$$

substitute x for v2

$$0.0005x^2-0.133x+6=0\\$$

 

$${\mathtt{0.000\: \!5}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{0.133}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{133}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{5\,689}}}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{5\,689}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{133}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{57.574\: \!540\: \!107\: \!467\: \!690\: \!7}}\\
{\mathtt{x}} = {\mathtt{208.425\: \!459\: \!892\: \!532\: \!309\: \!3}}\\
\end{array} \right\}$$

 

 $$v^2=57.574540\:\:\rightarrow v=\pm7.58779\:\: \mbox{approx}$$   or

$$v^2=208.42545989\:\:\rightarrow\:\:v=\pm14.4369\:\:\mbox{approx}$$

I think that is all okay.

Melody  May 8, 2014

14 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.