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(1-1/t^2)/(1/t-t) = -1/t

 

How??

 Jan 31, 2016

Best Answer 

 #2
avatar+129850 
+5

(1-1/t^2)/(1/t-t) = -1/t     get common denominators on top and bottom

 

(  [t^2 - 1] / t^2  )   / (  [ 1 - t^2] / t )   =       factor a -1 out of the numerator on the right

 

( - [ 1 - t^2] / t^2 )  / ( [ 1 - t^2] / t )  =

 

( - [ 1 - t^2] / t^2 )  * ( t / [ 1 - t^2] )   =

 

( - [ 1 - t^2] / [ 1 - t^2] ) * ( t / t^2 )  =

 

- t  / t^2   =

 

-1 / t

 

 

 

cool cool cool

 Jan 31, 2016
 #1
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+5

=  ( t^2 -1)/t^2   / (1-t^2)/t

 

= (t^2-1)/t^2   x   t/(1-t^2)  = (t^2 -1)/t  x   1/(1-t^2)     Multiply by  -1/-1

(1-t^2)/(-t)  x 1/(1-t^2) =   - 1/t

 Jan 31, 2016
 #2
avatar+129850 
+5
Best Answer

(1-1/t^2)/(1/t-t) = -1/t     get common denominators on top and bottom

 

(  [t^2 - 1] / t^2  )   / (  [ 1 - t^2] / t )   =       factor a -1 out of the numerator on the right

 

( - [ 1 - t^2] / t^2 )  / ( [ 1 - t^2] / t )  =

 

( - [ 1 - t^2] / t^2 )  * ( t / [ 1 - t^2] )   =

 

( - [ 1 - t^2] / [ 1 - t^2] ) * ( t / t^2 )  =

 

- t  / t^2   =

 

-1 / t

 

 

 

cool cool cool

CPhill Jan 31, 2016

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