+36 Hey CPhill, remember the question that I posted earlier, finding 1-100 with 2,0,2,1? Well, I've gotten some progress with that..
1 = 2 + 0 - 2 + 1
2 = (2 + 0) / 2 + 1
3 = 2^2 - 1 - 0
4 = 2^2 - 0/1
5 = 2 + 0 + 2 + 1
6 = (2 + 1)2 + 0
7 = 10/2 + 2
8 = (2 + 1)! + 2 - 0
9 = (2 + 1)^2 + 0/2
10 = (20/2) / 1
11 = 20 / 2 + 1
12 = 12 + 0/2
13 = 12 + (0/2)!
14 = 12 + 2 + 0
15 = C(10,2) / ( 2! + 0! )
16 = 2^ ( 0! + 1! + 2!)
17 = 20 - 2 -1
18 = 20 - (2/1)!
19 = 20 - 2! + 1!
20 = 20 / (2 -1)
21 = 20 + 2 - 1
22 = 20 + 2/1
23 = 20 + 2 + 1
24 = ( 12) ( 2 + 0)
25 = 122 + 0!
26 = 20 + (1 + 2)!
27 = (2 ! + 0! ) ^( 2 + 1)
28 = C(10-2, 2)
29 = [(2+0!)! / .2] -1
30 = (2 + 0!)! * (1/.2)
31 = 2^(1/.2) - 0!
32 = 10 + 22
33 = 2^(1/.2) + 0!
34 = (2^2)! + 10
35 = [ (2 + 1) 1] ^2 - 0!
36 = [ (2 + 1)! ] ^2 - 0
37 = 2! + 0!)! ^( 2) + 1
38 = (20-1) * 2
39 = 20*2 - 1
40 = 10 (2 + 2)
41 = 20 * 2 + 1
42 = 21*2 - 0
43 = 21 *2 + 0!
44 = 22(1 + 0!)
45 = p(10, 2)/2
46 =
47 = C(10,2) + 2
48 = (10/.2) - 2
49 =((2+1)! + 0!)^2
50 = 10^2/2
51 = 102/2
52 = (10/.2) + 2
53 = ( 12/.2 bar) - 0!
54 = ( 12/.2 bar) + 0
55 = (12 - 0!)/.2
56 = P(10-2,2)
57 =
58 =[ ( 2 + 0! )! / .1] - 2
59 = 12/.2 - 0!
60 = 20 ( 2 + 1)
61 = 12/.2 + 0!
62 = [( 2 + 0! )!/ .1] + 2
63 = 2^( [ 2 + 1]!) - 0!
64 = 2^([2 + 1)! ] + 0
65 = C(12,2) - 0!
66 = C(12,2) - 0
67 = C(12,2) + 0!
68 =
69 =
70 =
71 =
72 = (12) ( 2 + 0!)!
73 =
74 =
75 =
76 =
77 =
78 = C(12+0!, 2)
79 = [( 0! / .1 bar ) ^2] -2
80 = [2^( 2 + 0!)] / .1
81 =[( 2^0/.1 bar)^2]
82 =
83 = [ (0!/.1 bar)^2] +2
84 =
85 =
86 =
87 =
88 = P(10,2) - 2
89 = (20/.2 bar) - 1
90 = C(10,2) * 2
91 = ( 20/.2 bar) + 1
92 = P (10,2) +2
93 =
94 =
95 = (20 -1)/.2
96 =
97 =
98 = 10^2 - 2
99 = 20/.2 - 1
100 = 102 - 2
Could you possibly fill out ANY of the missing spots? Thank you so much!!
