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Hey CPhill, remember the question that I posted earlier, finding 1-100 with 2,0,2,1? Well, I've gotten some progress with that..

1 =  2 + 0 - 2 + 1

2  = (2 + 0) / 2  + 1

3  =  2^2 - 1 - 0

4  =  2^2  - 0/1

5 =  2 + 0 + 2 + 1

6 =  (2 + 1)2  + 0

7  =  10/2 + 2

8  =  (2 + 1)! + 2   - 0

9 =  (2 + 1)^2  + 0/2

10  = (20/2)  / 1

11  = 20 / 2 + 1

12  =  12  + 0/2

13  =   12 + (0/2)!

14  =  12 + 2 + 0

15  =  C(10,2) / ( 2! + 0! )

16  =   2^ ( 0! + 1!  + 2!)

17 = 20 - 2 -1 

18  =  20  - (2/1)!

19  = 20 - 2! + 1!

20 =   20 / (2 -1)

21  =  20 + 2  - 1

22  =  20 + 2/1

23  = 20 + 2 + 1

24  = ( 12) ( 2 + 0)

25 =   122  + 0!

26  =  20 + (1 + 2)!

27 = (2 ! + 0! ) ^( 2 + 1)

28 = C(10-2, 2)

29 = [(2+0!)! / .2] -1

30 = (2 + 0!)! * (1/.2)

31 = 2^(1/.2) - 0!

32 = 10  + 22

33 = 2^(1/.2) + 0!

34 = (2^2)! + 10

35 = [ (2 + 1) 1] ^2  - 0!

36 = [ (2 + 1)!  ] ^2  - 0

37 = 2! + 0!)! ^( 2)  +  1

38 = (20-1) * 2

39 =  20*2 - 1

40 = 10 (2 + 2)

41 =  20 * 2 + 1

42 = 21*2  - 0

43 = 21 *2  + 0!

44 = 22(1 + 0!)

45 = p(10, 2)/2

46 = 

47 = C(10,2) + 2

48 = (10/.2)  -  2

49 =((2+1)! + 0!)^2

50 = 10^2/2

51 = 102/2

52 = (10/.2) + 2

53 = ( 12/.2 bar) - 0!

54 = ( 12/.2 bar) + 0

55 = (12 - 0!)/.2

56 = P(10-2,2)

57 = 

58 =[ ( 2 + 0! )! / .1] -  2 

59 = 12/.2  - 0!

60 = 20 ( 2 + 1)

61 = 12/.2  + 0!

62 = [( 2 + 0! )!/ .1] + 2

63 = 2^( [ 2 + 1]!)  - 0!

64 = 2^([2 + 1)! ] + 0

65 = C(12,2) - 0!

66 = C(12,2) - 0 

67 = C(12,2)  + 0!

68 = 

69 = 

70 = 

71 = 

72 =  (12)  ( 2 + 0!)!

73 = 

74 = 

75 = 

76 =

77 =

78 = C(12+0!, 2)

79 = [( 0! / .1 bar ) ^2] -2

80 = [2^( 2 + 0!)] / .1

81 =[( 2^0/.1 bar)^2]

82 =

83 = [ (0!/.1 bar)^2] +2

84 =

85 =

86 =

87 =

88 = P(10,2) - 2

89 = (20/.2 bar) - 1

90 = C(10,2) * 2

91 = ( 20/.2 bar) + 1

92 = P (10,2) +2

93 =

94 =

95 = (20 -1)/.2

96 =

97 =

98 = 10^2  - 2

99 = 20/.2 - 1

100 = 102  - 2

 

Could you possibly fill out ANY of the missing spots? Thank you so much!!

 
 Dec 31, 2020

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