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1.2=((0.5*5.08*18*x^2))/(x/3)/((0.5*0.295*18*(1.2+x^2))*((1.2+x)/3))

Guest Sep 25, 2014

Best Answer 

 #1
avatar+92221 
+5

There was one too many brackets so I may not have answered the question intended.

I also think you may have left out a square of put an extra one in.

 

$$\\1.2=\frac{0.5*5.08*18*x^2}{x/3}\div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{0.5*5.08*18*x^2}{1}\times \frac{3}{x}\div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{3*0.5*5.08*18*x}{1} \div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{3*0.5*5.08*18*x}{(0.5*0.295*18*(1.2+x^2))} *\frac{1.2+x}{3}\\
\\1.2=\frac{3*5.08*x}{0.295*(1.2+x^2)} *\frac{1.2+x}{3}\\
\\1.2=\frac{5.08x(1.2+x)}{0.295(1.2+x^2)} \\
\\1.2(0.295(1.2+x^2))=5.08x(1.2+x) \\
\\0.354(1.2+x^2))=5.08x(1.2+x) \\
\\0.4248+0.354x^2=6.096x+5.08x^2 \\
\\0=4.726x^2+6.096x-0.4248\\$$

 

Now you can solve it using the quadratic formula.

Melody  Sep 26, 2014
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1+0 Answers

 #1
avatar+92221 
+5
Best Answer

There was one too many brackets so I may not have answered the question intended.

I also think you may have left out a square of put an extra one in.

 

$$\\1.2=\frac{0.5*5.08*18*x^2}{x/3}\div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{0.5*5.08*18*x^2}{1}\times \frac{3}{x}\div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{3*0.5*5.08*18*x}{1} \div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{3*0.5*5.08*18*x}{(0.5*0.295*18*(1.2+x^2))} *\frac{1.2+x}{3}\\
\\1.2=\frac{3*5.08*x}{0.295*(1.2+x^2)} *\frac{1.2+x}{3}\\
\\1.2=\frac{5.08x(1.2+x)}{0.295(1.2+x^2)} \\
\\1.2(0.295(1.2+x^2))=5.08x(1.2+x) \\
\\0.354(1.2+x^2))=5.08x(1.2+x) \\
\\0.4248+0.354x^2=6.096x+5.08x^2 \\
\\0=4.726x^2+6.096x-0.4248\\$$

 

Now you can solve it using the quadratic formula.

Melody  Sep 26, 2014

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