+0  
 
0
468
1
avatar

1.2=((0.5*5.08*18*x^2))/(x/3)/((0.5*0.295*18*(1.2+x^2))*((1.2+x)/3))

Guest Sep 25, 2014

Best Answer 

 #1
avatar+94202 
+5

There was one too many brackets so I may not have answered the question intended.

I also think you may have left out a square of put an extra one in.

 

$$\\1.2=\frac{0.5*5.08*18*x^2}{x/3}\div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{0.5*5.08*18*x^2}{1}\times \frac{3}{x}\div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{3*0.5*5.08*18*x}{1} \div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{3*0.5*5.08*18*x}{(0.5*0.295*18*(1.2+x^2))} *\frac{1.2+x}{3}\\
\\1.2=\frac{3*5.08*x}{0.295*(1.2+x^2)} *\frac{1.2+x}{3}\\
\\1.2=\frac{5.08x(1.2+x)}{0.295(1.2+x^2)} \\
\\1.2(0.295(1.2+x^2))=5.08x(1.2+x) \\
\\0.354(1.2+x^2))=5.08x(1.2+x) \\
\\0.4248+0.354x^2=6.096x+5.08x^2 \\
\\0=4.726x^2+6.096x-0.4248\\$$

 

Now you can solve it using the quadratic formula.

Melody  Sep 26, 2014
 #1
avatar+94202 
+5
Best Answer

There was one too many brackets so I may not have answered the question intended.

I also think you may have left out a square of put an extra one in.

 

$$\\1.2=\frac{0.5*5.08*18*x^2}{x/3}\div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{0.5*5.08*18*x^2}{1}\times \frac{3}{x}\div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{3*0.5*5.08*18*x}{1} \div(0.5*0.295*18*(1.2+x^2))*\frac{1.2+x}{3}\\
\\1.2=\frac{3*0.5*5.08*18*x}{(0.5*0.295*18*(1.2+x^2))} *\frac{1.2+x}{3}\\
\\1.2=\frac{3*5.08*x}{0.295*(1.2+x^2)} *\frac{1.2+x}{3}\\
\\1.2=\frac{5.08x(1.2+x)}{0.295(1.2+x^2)} \\
\\1.2(0.295(1.2+x^2))=5.08x(1.2+x) \\
\\0.354(1.2+x^2))=5.08x(1.2+x) \\
\\0.4248+0.354x^2=6.096x+5.08x^2 \\
\\0=4.726x^2+6.096x-0.4248\\$$

 

Now you can solve it using the quadratic formula.

Melody  Sep 26, 2014

23 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.