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# 1/2x^(-1/2) *((2xe^x)/ln(3x^2 +2))

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What is

1/2x^(-1/2) *((2xe^x)/ln(3x^2 +2))

Sep 1, 2014

#1
+95334
+5

$$1/2x^{-1/2} *((2xe^x)/ln(3x^2 +2))\\\\ =\frac{x^{-1/2}}{\not{2}}*\frac{\not{2}xe^x}{ln(3x^2 +2)}\\\\ =\frac{1}{1}*\frac{x^{(1-1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{x^{(1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{\sqrt{x}e^x}{ln(3x^2 +2)}\\\\$$

I don't think that there is anything else to be done with this.

Has anyone got any further/different thoughts?

Sep 1, 2014

#1
+95334
+5

$$1/2x^{-1/2} *((2xe^x)/ln(3x^2 +2))\\\\ =\frac{x^{-1/2}}{\not{2}}*\frac{\not{2}xe^x}{ln(3x^2 +2)}\\\\ =\frac{1}{1}*\frac{x^{(1-1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{x^{(1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{\sqrt{x}e^x}{ln(3x^2 +2)}\\\\$$

I don't think that there is anything else to be done with this.

Has anyone got any further/different thoughts?

Melody Sep 1, 2014