+0

# 1/2x^(-1/2) *((2xe^x)/ln(3x^2 +2))

0
268
1

What is

1/2x^(-1/2) *((2xe^x)/ln(3x^2 +2))

Guest Sep 1, 2014

#1
+91479
+5

$$1/2x^{-1/2} *((2xe^x)/ln(3x^2 +2))\\\\ =\frac{x^{-1/2}}{\not{2}}*\frac{\not{2}xe^x}{ln(3x^2 +2)}\\\\ =\frac{1}{1}*\frac{x^{(1-1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{x^{(1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{\sqrt{x}e^x}{ln(3x^2 +2)}\\\\$$

I don't think that there is anything else to be done with this.

Has anyone got any further/different thoughts?

Melody  Sep 1, 2014
Sort:

#1
+91479
+5

$$1/2x^{-1/2} *((2xe^x)/ln(3x^2 +2))\\\\ =\frac{x^{-1/2}}{\not{2}}*\frac{\not{2}xe^x}{ln(3x^2 +2)}\\\\ =\frac{1}{1}*\frac{x^{(1-1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{x^{(1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{\sqrt{x}e^x}{ln(3x^2 +2)}\\\\$$

I don't think that there is anything else to be done with this.

Has anyone got any further/different thoughts?

Melody  Sep 1, 2014

### 8 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details