+0

# 1/2x^(-1/2) *((2xe^x)/ln(3x^2 +2))

0
401
1

What is

1/2x^(-1/2) *((2xe^x)/ln(3x^2 +2))

Guest Sep 1, 2014

#1
+92781
+5

$$1/2x^{-1/2} *((2xe^x)/ln(3x^2 +2))\\\\ =\frac{x^{-1/2}}{\not{2}}*\frac{\not{2}xe^x}{ln(3x^2 +2)}\\\\ =\frac{1}{1}*\frac{x^{(1-1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{x^{(1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{\sqrt{x}e^x}{ln(3x^2 +2)}\\\\$$

I don't think that there is anything else to be done with this.

Has anyone got any further/different thoughts?

Melody  Sep 1, 2014
#1
+92781
+5

$$1/2x^{-1/2} *((2xe^x)/ln(3x^2 +2))\\\\ =\frac{x^{-1/2}}{\not{2}}*\frac{\not{2}xe^x}{ln(3x^2 +2)}\\\\ =\frac{1}{1}*\frac{x^{(1-1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{x^{(1/2)}e^x}{ln(3x^2 +2)}\\\\ =\frac{\sqrt{x}e^x}{ln(3x^2 +2)}\\\\$$

I don't think that there is anything else to be done with this.

Has anyone got any further/different thoughts?

Melody  Sep 1, 2014