1/4 of Mie's savings was equal to 2/5 of Cheko's savings. When Cheko increased his savings by $70 and Mie spent $134, they had the same amount of savings. How much savings did Cheko have finally?
M==Mie, C==Cheko
1/4M ==2/5C,
M - 134==C + 70, solve for C, M
Use substitution to get:
M==$544 - what Mie started with
C ==$340 - what Cheko started with.
$340 + $70 ==$410 - what Cheko ended up with.
$544 - $134==$410 - what Mie ended with
$70 + $134 = $204
3 units --- $204
1 unit --- $68
5 x $68 + $70 = $410 (Cheko)
Answer: $410
U may draw model for a clearer answer.
