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# 1/6 + 1/8 - 1/48, or is it?

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A six-sided die (with numbers 1 through 6) and an eight-sided die (with numbers 1 through 8) are rolled. What is the probability that there is exactly one 6 showing? Express your answer as a common fraction.

1/6 for the first die

1/8 for the second die

1/48, the probability that BOTH will roll a 6.

1/6 + 1/8 - 1/48?

Jun 3, 2020

#1
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No,

$$1\over6$$ for the 6-sided die

$$1\over8$$ for the 8-sided die

$$1\over{6}$$+$$1\over8$$=$$7\over24$$

Jun 3, 2020
#2
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$$\frac{1}{6}\cdot\frac{7}{8}=\frac{7}{48}$$

1/6 for the probability of  rolling a 6, 7/8 is the probability of not rolling a 6.

$$\frac{1}{8}\cdot\frac{5}{6}=\frac{5}{48}$$

1/8 for the probability of  rolling a 6, 5/6 is the probability of not rolling a 6.

$$\frac{7}{48}+\frac{5}{48}=\frac{12}{48}=\frac{1}{4}$$