+0  
 
-2
192
2
avatar

A six-sided die (with numbers 1 through 6) and an eight-sided die (with numbers 1 through 8) are rolled. What is the probability that there is exactly one 6 showing? Express your answer as a common fraction.

 

1/6 for the first die

1/8 for the second die

1/48, the probability that BOTH will roll a 6.

 

1/6 + 1/8 - 1/48?

 Jun 3, 2020
 #1
avatar+176 
0

No, 

\(1\over6\) for the 6-sided die

\(1\over8\) for the 8-sided die

 

\(1\over{6}\)+\(1\over8\)=\(7\over24\)

 Jun 3, 2020
 #2
avatar
0

\(\frac{1}{6}\cdot\frac{7}{8}=\frac{7}{48}\)

 

1/6 for the probability of  rolling a 6, 7/8 is the probability of not rolling a 6.

 

\(\frac{1}{8}\cdot\frac{5}{6}=\frac{5}{48}\)

 

1/8 for the probability of  rolling a 6, 5/6 is the probability of not rolling a 6.

 

\(\frac{7}{48}+\frac{5}{48}=\frac{12}{48}=\frac{1}{4}\)

 

Add the probabilities together.

 Jun 3, 2020

10 Online Users

avatar