+2446 I will solve for x in the equation 18(56x−24)=87(21x−7)+7.
| 18(56x−24)=87(21x−7)+7 | Distribute the 1/8 to both terms inside of the parentheses. |
| 7x−3=87(21x−7)+7 | Multiply both sides by 7 to get rid of all the fractions in this equation. |
| 49x−21=8(21x−7)+49 | Inside the parentheses, let's factor our a GCF of 7 from both terms of the parentheses. |
| 8(21x−7)=(8∗7)(3x−1)=56(3x−1) | Now, plug that back into the equation. |
| 49x−21=56(3x−1)+49 | Divide all sides of the equation by its GCF, 7. This should ease computation since the numbers will be easier to work with. |
| 7x−3=8(3x−1)+7 | Distribute the 8 to both terms in the parentheses. |
| 7x−3=24x−8+7 | Simplify the left hand side. |
| 7x−3=24x−1 | Subtract 7x on both sides. |
| −3=17x−1 | Add 1 to both sides. |
| −2=17x | Divide by 17 on both sides. |
| x=−217 |
