+0

1/cosx(tanx-1)=tanx + cotx/tanx-cotx

0
398
2

1/cosx(tanx-1)=tanx + cotx/tanx-cotx

plis helpme

Oct 1, 2017

#1
+99282
+1

1/cosx(tanx-1)=tanx + cotx/tanx-cotx

You have not used enough brackets, so your question is not clear.

This is what you have asked.  Is it what you really want?

$$\frac{1}{cosx(tanx-1)}=tanx + \frac{cotx}{tanx}-cotx$$

.
Oct 2, 2017
#2
+98090
+1

According to WolframAlpha.....as written, this isn't an identity........

I've been trying to find some other arrangement that might "work"  ....but I haven't hit on any, yet.....!!!!

Oct 2, 2017