1. In the SmallState Lottery, three white b***s are drawn (at random) from twenty b***s numbered 1 through 20, and a blue SuperBall is

1. For the first one, we have this many possibile outcomes :

C(20,3) * 10  = 11,400   ...so....the probability of winning on one ticket is  1 /11,400  = 0.0000877192982456 = about .0088%

Thanks Chris :)

2. For the second one.....

Let A be the probabilty of choosing 3 b***s out of 20 

Let B be the probability of choosing one ball out of 10

So

P(P or B)  =  1/C(20,3)  + 1/10   =  1/1140 + 1/10   =  23/228 =  about 10%

I get a slightly different answer for the second part:

prob of matching 3 white b***s  = 3/20 * 2/19 * 1/18 = 6/(20*19*18)

prob of matching 1st and 2nd but not 3rd = 3/20 * 2/19 * 17/18 = 6*17/(20*19*18)

prob of matching 1st and 3rd but not 2nd = 3/20 * 17/19 * 2/18  = 6*17/(20*19*18)

prob of matching 2nd and 3rd but not 1st = 17/20 * 3/19 * 2/18  = 6*17/(20*19*18)

prob of matching blue ball = 1/10

Overall probability = 6*(1+3*17)/(20*19*18) +1/10 = 83/570 ≈ 0.146

I think Chris's probability (23/228) is that of getting all three white b***s or the blue ball, rather than at least two white b***s or the blue ball.

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Why is b***s considered a swear word?

don't we have to multiply probablities?

You don't have to multiply probabilities for the second part because it says or. Or in a probability statement means that you add, AND means you multiply

I need some help with part b too. Both the above answers are wrong.

67/475