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1. Noemi wants to divide 2x2−x+4 by x−5 using synthetic division.

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1. Noemi wants to divide 2x2−x+4 by x−5 using synthetic division.

What is the correct process?

Guest Oct 23, 2017

#1
+17655
+1

You begin by placing the opposite of the number (of the divisor) into the box on the top left.

Then, you bring down the coefficient of the squared term (the '2').

Now, you multiply the number in the box (the '5') times the coefficient of the squared term (the '2') and you place the answer (a '10') into the second column. This column now contains a '-1' and a '10; add these together, getting '9'.

Finally, multiply the number in the box (the '5') times the result of the second column (the '9'), getting '45'. Place this number into the third column and add down, getting '49'.

The division results in a quotient of '2x + 9' and a remainder of '49'.

geno3141  Oct 23, 2017
Sort:

#1
+17655
+1

You begin by placing the opposite of the number (of the divisor) into the box on the top left.

Then, you bring down the coefficient of the squared term (the '2').

Now, you multiply the number in the box (the '5') times the coefficient of the squared term (the '2') and you place the answer (a '10') into the second column. This column now contains a '-1' and a '10; add these together, getting '9'.

Finally, multiply the number in the box (the '5') times the result of the second column (the '9'), getting '45'. Place this number into the third column and add down, getting '49'.

The division results in a quotient of '2x + 9' and a remainder of '49'.

geno3141  Oct 23, 2017

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