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10 pails of water can fill 5/8 of a tank. Another 4 pails and 5 jugs of water are needed to fill the tank to its brim. How many jugs of water can the tank hold?

 Feb 11, 2015

Best Answer 

 #1
avatar+20850 
+10

10 pails of water can fill 5/8 of a tank. Another 4 pails and 5 jugs of water are needed to fill the tank to its brim. How many jugs of water can the tank hold ?

$$\dfrac{ \frac{5}{8}\ \mathrm{tank} } { 10\ \mathrm{pails}} * 14 \ \mathrm{pails} = \frac{5*14}{8*10} \ \mathrm{tank} = \frac{7}{8}\ \mathrm{tank} \\\\
\frac{7}{8}\ \mathrm{tank} + 5\ \mathrm{jugs} = 1\ \mathrm{tank} \\
5\ \mathrm{jugs} = 1\ \mathrm{tank}- \frac{7}{8}\ \mathrm{tank} =\frac{1}{8}\ \mathrm{tank} \quad | \quad * 8\\
5*8\ \mathrm{jugs} = \frac{8}{8}\ \mathrm{tank} \\
40\ \mathrm{jugs} = 1\ \mathrm{tank} \\$$

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 Feb 11, 2015
 #1
avatar+20850 
+10
Best Answer

10 pails of water can fill 5/8 of a tank. Another 4 pails and 5 jugs of water are needed to fill the tank to its brim. How many jugs of water can the tank hold ?

$$\dfrac{ \frac{5}{8}\ \mathrm{tank} } { 10\ \mathrm{pails}} * 14 \ \mathrm{pails} = \frac{5*14}{8*10} \ \mathrm{tank} = \frac{7}{8}\ \mathrm{tank} \\\\
\frac{7}{8}\ \mathrm{tank} + 5\ \mathrm{jugs} = 1\ \mathrm{tank} \\
5\ \mathrm{jugs} = 1\ \mathrm{tank}- \frac{7}{8}\ \mathrm{tank} =\frac{1}{8}\ \mathrm{tank} \quad | \quad * 8\\
5*8\ \mathrm{jugs} = \frac{8}{8}\ \mathrm{tank} \\
40\ \mathrm{jugs} = 1\ \mathrm{tank} \\$$

heureka Feb 11, 2015
 #2
avatar+94607 
+5

Thanks, heureka....here's another way to consider this....

If 10 pails fill 5/8 of the tank, than 10 / (5/8)  = 80/5 = 16 pails fill the whole tank.

Then, when 4 more pails are added, 14/16 of the the tank must be filled.

And 5 jugs fill the other 2/16 = 1/8.  So, 5/(1/8)  = 5 * 8  = 40 jugs fill the whole tank....!!!

 

 Feb 11, 2015

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