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#2**+10 **

I beleve this person wants the cross-product ....(0, 11, 2) x (0, 5, 3)

This will form a vector that is perpendicular to both of these

To get the x coordinate, we have

(11* 3) - (2 * 5) = 33 - 10 = 23

To get the y coordinate, we have

(2*0) - (0* 3) = 0

To get the z coordinate, we have

(0 * 5) - (11* 0) = 0

So....our cross-product vector is (23, 0, 0)

This makes sense......since both of the given vectors lie in the y-z plane......the vector perpendicular to both should just lie along the x axis....!!!

Here's a pic.....

Yuo can read more about this proceedure, here ......http://www.mathsisfun.com/algebra/vectors-cross-product.html

CPhill Feb 22, 2015

#2**+10 **

Best Answer

I beleve this person wants the cross-product ....(0, 11, 2) x (0, 5, 3)

This will form a vector that is perpendicular to both of these

To get the x coordinate, we have

(11* 3) - (2 * 5) = 33 - 10 = 23

To get the y coordinate, we have

(2*0) - (0* 3) = 0

To get the z coordinate, we have

(0 * 5) - (11* 0) = 0

So....our cross-product vector is (23, 0, 0)

This makes sense......since both of the given vectors lie in the y-z plane......the vector perpendicular to both should just lie along the x axis....!!!

Here's a pic.....

Yuo can read more about this proceedure, here ......http://www.mathsisfun.com/algebra/vectors-cross-product.html

CPhill Feb 22, 2015