Your question makes no sense.
I expect the bracket is supposed to contain 11-8 ?
Agree.
But just trying:
Factorial can be defined as
n!=n×(n−1)×(n−2)...
But what is strange is that if I plug -3! into the calculator,
(-3)! = 1
So.... kind of weird.
Let's just say its somehow 1.
11!/8! =
11 * 10 * 9 =
990
thanks calc user
\(11C8\\ = \frac{11! }{8!(11-8)!}\\ = \frac{8!*9*10*11 }{8!(3)!}\\ = \frac{9*10*11 }{(3)!}\\ = \frac{9*10*11 }{2*3}\\ = \frac{3*5*11 }{1}\\ =165\)
yes I think melody's is correct!
What the guest is trying to ask is a combination question.