-12((3x-4)/(3)-(3-4x)/(4)-(6-2x)/(6))
Please solve with all steps included
+9481 I answered a question nearly identical to this yesterday, but maybe my answer was unclear.
Here is another way of looking at it.
-12((3x-4)/(3)-(3-4x)/(4)-(6-2x)/(6)) In fraction form, this is
\(=\,-12(\frac{3x-4}{3}-\frac{3-4x}{4}-\frac{6-2x}{6})\)
\(=\,-12[\frac13(3x-4)-\frac14(3-4x)-\frac16(6-2x)]\) We can distribute the -12 like this...
\(=\,(-12)(\frac13)(3x-4)-(-12)(\frac14)(3-4x)-(-12)(\frac16)(6-2x) \\~\\ =\,(\frac{-12}3)(3x-4)-(\frac{-12}4)(3-4x)-(\frac{-12}6)(6-2x) \\~\\ =\,(-4)(3x-4)-(-3)(3-4x)-(-2)(6-2x) \\~\\ =\,(-4)(3x-4)+(3)(3-4x)+(2)(6-2x) \\~\\ =\,(-4)(3x)+(-4)(-4)+(3)(3)+(3)(-4x)+(2)(6)+(2)(-2x) \\~\\ =\,-12x+16+9-12x+12-4x \\~\\ =\,-28x+37\)
+9481 I answered a question nearly identical to this yesterday, but maybe my answer was unclear.
Here is another way of looking at it.
-12((3x-4)/(3)-(3-4x)/(4)-(6-2x)/(6)) In fraction form, this is
\(=\,-12(\frac{3x-4}{3}-\frac{3-4x}{4}-\frac{6-2x}{6})\)
\(=\,-12[\frac13(3x-4)-\frac14(3-4x)-\frac16(6-2x)]\) We can distribute the -12 like this...
\(=\,(-12)(\frac13)(3x-4)-(-12)(\frac14)(3-4x)-(-12)(\frac16)(6-2x) \\~\\ =\,(\frac{-12}3)(3x-4)-(\frac{-12}4)(3-4x)-(\frac{-12}6)(6-2x) \\~\\ =\,(-4)(3x-4)-(-3)(3-4x)-(-2)(6-2x) \\~\\ =\,(-4)(3x-4)+(3)(3-4x)+(2)(6-2x) \\~\\ =\,(-4)(3x)+(-4)(-4)+(3)(3)+(3)(-4x)+(2)(6)+(2)(-2x) \\~\\ =\,-12x+16+9-12x+12-4x \\~\\ =\,-28x+37\)
