Need to solve for r in this problem, ln stands for natural log
1800=-5000ln r
+259 ln(x) = y
x = e^y
-5000ln(r) = 1800. I / -5000
ln(r) = 1800 / -5000
r = e^(1800/-5000)
r = e^-0.36
r = 1/(e^0.36)
I think. Im not 100 sure about the answer
+36922 1800 / -5000 = ln r
-.36 = ln r
e^(-.36) = r
r = .69768 Yep, Amnesia had it correct !
