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Joyce, Ken and Brandon sold some tickets. Joyce sold 1/10 of the tickets. Ken sold 6 more tickets than Joyce. Brandon sold 82 tickets. Find the number of tickets Ken sold.

 Aug 19, 2021
 #1
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Set all of the tickets the three people sold as X.

 

Joyce: 1/10X

Ken: 1/10X+6

Brandon: 82

 

we get 4/5X= 88, thus 1/X = 22, thus X = 110

 

Brandon sold 82(he really sold A LOT),

Joyce sold 11,

and Ken sold 17!

 

You can plug the answers back and check if you want!

 Aug 19, 2021
 #2
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x/10 + x/10 + 6 + 82 = x

 

x = 110

 

Ken sold   x/10 + 6 = 17

 Aug 19, 2021

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