Joyce, Ken and Brandon sold some tickets. Joyce sold 1/10 of the tickets. Ken sold 6 more tickets than Joyce. Brandon sold 82 tickets. Find the number of tickets Ken sold.

Guest Aug 19, 2021

#1**-3 **

Set all of the tickets the three people sold as X.

Joyce: 1/10X

Ken: 1/10X+6

Brandon: 82

we get 4/5X= 88, thus 1/X = 22, thus X = 110

Brandon sold 82(he really sold A LOT),

Joyce sold 11,

and Ken sold 17!

You can plug the answers back and check if you want!

OrangeJuicy Aug 19, 2021