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The ocean middle school 6th grade class voted on whether to hold their class party on the second or third of april. Holding the party on april third won 62% of the vote.


a.What percent of the 6th grade class voted to have the party on the second?


b.there are 355 6th graders at oceanview middle school.


1.How any voted for having the party on the third?


2. How many voted for having the party on the second?


3. The planning committee is expecting 80% of the class to attend the party. How many students are they expecting?

 Nov 16, 2014

Best Answer 

 #3
avatar+1975 
+10

thanks for making sure i was right CPhill, i wasnt sure about those :)

 Nov 17, 2014
 #1
avatar+1975 
+10

a. all you have to do is subtract 62 from 100 so 38% of the 6th grade class voted to have the party on the second

 

b1. well i thought to solve this one you would multiply 355 and .62 together but that equals 220.1 and you cant have .1 of a kid... so im not sure about b1

 

b2. subtract b1 from 355

 

3. i did 355 x .80 and you get 284 students

 

i appoligize ahead of time if i did anything wrong!

 Nov 16, 2014
 #2
avatar+129933 
+5

The ocean middle school 6th grade class voted on whether to hold their class party on the second or third of april. Holding the party on april third won 62% of the vote.

 

a.What percent of the 6th grade class voted to have the party on the second?

 See saseflower's answer.....

b.there are 355 6th graders at oceanview middle school.

 

1.How any voted for having the party on the third?

355 x 62%  = about 220....again...saseflower is right on the money !!!

2. How many voted for having the party on the second?

355 - 220 = 135   (saseflower has the correct proceedure !!)

3. The planning committee is expecting 80% of the class to attend the party. How many students are they expecting?

Again, saseflower is correct !!

 

 Nov 17, 2014
 #3
avatar+1975 
+10
Best Answer

thanks for making sure i was right CPhill, i wasnt sure about those :)

saseflower Nov 17, 2014

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