+0  
 
0
563
9
avatar

2/(1*2*3)+....+2/(9*10*11)

Guest Apr 25, 2015

Best Answer 

 #8
avatar+27251 
+5

I think you could probably do 1/2 - 1/[(n+1)(n+2)] on a hand-held without too much difficulty.

.

Alan  Apr 25, 2015
 #1
avatar+94203 
+5

The meaning of this question is not clear.   

you should have shown us the second term :/

Melody  Apr 25, 2015
 #2
avatar+27251 
+5

Summation:

.

Alan  Apr 25, 2015
 #3
avatar+94203 
+3

Yes Alan I agree that is the most likely meaning. :)

Melody  Apr 25, 2015
 #4
avatar+27251 
+5

If the questioner doesn't mean that then he/she definitely hasn't provided enough information!

.

Alan  Apr 25, 2015
 #5
avatar+94203 
0

Alan,  I am wondering,

Is  there a relatively easy way to do this on a normal hand held calc?

OR the web2 calc.

I mean without doing each bit seperately?

Melody  Apr 25, 2015
 #6
avatar+27251 
+5

One could use the general expression:

General expression for summation

I just got Mathcad to obtain this.  No doubt Wolfram Alpha would produce the same thing.

Alan  Apr 25, 2015
 #7
avatar+94203 
0

Thanks Alan, they are not exactly hand held calcs :))

Melody  Apr 25, 2015
 #8
avatar+27251 
+5
Best Answer

I think you could probably do 1/2 - 1/[(n+1)(n+2)] on a hand-held without too much difficulty.

.

Alan  Apr 25, 2015
 #9
avatar+94203 
0

Yes I could - thanks Alan :)

Melody  Apr 25, 2015

22 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.