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2/(1*2*3)+....+2/(9*10*11)

Guest Apr 25, 2015

Best Answer 

 #8
avatar+26329 
+5

I think you could probably do 1/2 - 1/[(n+1)(n+2)] on a hand-held without too much difficulty.

.

Alan  Apr 25, 2015
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9+0 Answers

 #1
avatar+91053 
+5

The meaning of this question is not clear.   

you should have shown us the second term :/

Melody  Apr 25, 2015
 #2
avatar+26329 
+5

Summation:

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Alan  Apr 25, 2015
 #3
avatar+91053 
+3

Yes Alan I agree that is the most likely meaning. :)

Melody  Apr 25, 2015
 #4
avatar+26329 
+5

If the questioner doesn't mean that then he/she definitely hasn't provided enough information!

.

Alan  Apr 25, 2015
 #5
avatar+91053 
0

Alan,  I am wondering,

Is  there a relatively easy way to do this on a normal hand held calc?

OR the web2 calc.

I mean without doing each bit seperately?

Melody  Apr 25, 2015
 #6
avatar+26329 
+5

One could use the general expression:

General expression for summation

I just got Mathcad to obtain this.  No doubt Wolfram Alpha would produce the same thing.

Alan  Apr 25, 2015
 #7
avatar+91053 
0

Thanks Alan, they are not exactly hand held calcs :))

Melody  Apr 25, 2015
 #8
avatar+26329 
+5
Best Answer

I think you could probably do 1/2 - 1/[(n+1)(n+2)] on a hand-held without too much difficulty.

.

Alan  Apr 25, 2015
 #9
avatar+91053 
0

Yes I could - thanks Alan :)

Melody  Apr 25, 2015

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