∛2×∛14

(2)^(1/3)  * (14)^(1/3)   =    (28)^1/3  

We use the fact that $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ to get that $\sqrt[3]{2} \cdot \sqrt[3]{14} = \sqrt[3]{2 \cdot 14} = \boxed{\sqrt[3]{28}}$.

Hoping this helped,

asdf334