1. The graph of the equation y=ax^2 + bx + c, where a, b, and c are constants, is a parabola with axis of symmetry x = -3. Find b/a
2. The vertex of a parabola is at (12, -4), and its axis of symmetry is vertical. One of the x-intercepts is at (15, 0). What is the x-coordinate of the other x-intercept?
+37157 1 Axis of symmetry will be the x value of the vertex given by -b/2a = -3 then b/a = -3* -2 = 6
2 the other intercept will be the same distance from the vertex except on THE OTHER SIDE OF THE VERTEX
9,0 12 - 4 15, 0
