1. The vertex of a parabola is at (12,4), and its axis of symmetry is vertical. One of the x-intercepts is at (15,0). What is the -coordinate of the other -intercept?
2. The x-intercepts of the parabola y=x^2+bx+c are (-3,0) and (5,0) Find the equation of the parabola, and submit your answer in y=ax^2+b+c form.
The axis of symmetry is just that....the axis of symmetry....so the zeroes are equal distances from the axis ...but on opposite sides
on zero is 15,0 then the axis of symmetry is x = 12 then the other zero is 9,0
you are given two zeroes x = -3 and x = 5
so the equation becomes y = (x+3)(x-5) expand to the form requested ....