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If f(x)=x^3+3x^2+3x+1, find f(f^-1(2010)).

 

If f(x) = 1/(x + 2) what is f(f(1))?

 Jun 20, 2020
edited by Guest  Jun 21, 2020
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1. The answer is 2010 because finding the inverse is finding the f(x) that results in 2010 when plugged into x^2+3x^2+3x+1. When we get the inverse, we then have f(inverse), which is plugging it straight back into x^2+3x^2+3x+1. Then the result is the same.

2. f(f(1)

=f(1/1+2)

=f(1/3)

=1/(1/3+2)

=1/7/3

=3/7

 Jun 21, 2020
edited by gwenspooner85  Jun 21, 2020

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