If f(x)=x^3+3x^2+3x+1, find f(f^-1(2010)).
If f(x) = 1/(x + 2) what is f(f(1))?
+781 1. The answer is 2010 because finding the inverse is finding the f(x) that results in 2010 when plugged into x^2+3x^2+3x+1. When we get the inverse, we then have f(inverse), which is plugging it straight back into x^2+3x^2+3x+1. Then the result is the same.
2. f(f(1)
=f(1/1+2)
=f(1/3)
=1/(1/3+2)
=1/7/3
=3/7
