+0  
 
+1
71
5
avatar+1164 

2 questions, plz help!

RainbowPanda  Apr 24, 2018
 #1
avatar+2765 
+3

I'll provide a solution later:

 1. \(y = -\frac{1}{8}x^2+2\)

tertre  Apr 24, 2018
 #2
avatar+2765 
+4

Ah, here it is!

The vertex has to be right in between them, so the vertex is \((0, 2)\). Now, we use the equation \((x-h)^2=4p(y-k)\)\(p = -2\) , because that is the directed distance between the vertex and focus. We get than \(x^2 = -8(y-2)\), so 

 

\(\boxed{y = -\frac{1}{8}x^2+2}\) is the desired equation.

 

smileysmiley

tertre  Apr 25, 2018
 #3
avatar+1164 
+1

Thank you so much, but my teacher says it's \(y=- \frac{x^2}{8}+2\)

RainbowPanda  Apr 25, 2018
 #4
avatar+1164 
+1

I believe this will work, ty ^-^

RainbowPanda  Apr 25, 2018
 #5
avatar+2765 
+1

No problem, cool

CPhill, can I use your glasses? smiley

tertre  Apr 25, 2018

11 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.