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2 questions, plz help!

 Apr 24, 2018
 #1
avatar+3994 
+3

I'll provide a solution later:

 1. \(y = -\frac{1}{8}x^2+2\)

.
 Apr 24, 2018
 #2
avatar+3994 
+4

Ah, here it is!

The vertex has to be right in between them, so the vertex is \((0, 2)\). Now, we use the equation \((x-h)^2=4p(y-k)\)\(p = -2\) , because that is the directed distance between the vertex and focus. We get than \(x^2 = -8(y-2)\), so 

 

\(\boxed{y = -\frac{1}{8}x^2+2}\) is the desired equation.

 

smileysmiley

 Apr 25, 2018
 #3
avatar+2442 
+1

Thank you so much, but my teacher says it's \(y=- \frac{x^2}{8}+2\)

RainbowPanda  Apr 25, 2018
 #4
avatar+2442 
+1

I believe this will work, ty ^-^

RainbowPanda  Apr 25, 2018
 #5
avatar+3994 
+1

No problem, cool

CPhill, can I use your glasses? smiley

tertre  Apr 25, 2018

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