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# 2 questions, plz help!

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2 questions, plz help!

Apr 24, 2018

#1
+3731
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I'll provide a solution later:

1. $$y = -\frac{1}{8}x^2+2$$

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Apr 24, 2018
#2
+3731
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Ah, here it is!

The vertex has to be right in between them, so the vertex is $$(0, 2)$$. Now, we use the equation $$(x-h)^2=4p(y-k)$$$$p = -2$$ , because that is the directed distance between the vertex and focus. We get than $$x^2 = -8(y-2)$$, so

$$\boxed{y = -\frac{1}{8}x^2+2}$$ is the desired equation.

Apr 25, 2018
#3
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Thank you so much, but my teacher says it's $$y=- \frac{x^2}{8}+2$$

RainbowPanda  Apr 25, 2018
#4
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I believe this will work, ty ^-^

RainbowPanda  Apr 25, 2018
#5
+3731
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No problem,

CPhill, can I use your glasses?

tertre  Apr 25, 2018