We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

+0

# 2 questions, plz help!

+1
202
5
+2448

2 questions, plz help!

Apr 24, 2018

### 5+0 Answers

#1
+4286
+3

I'll provide a solution later:

1. $$y = -\frac{1}{8}x^2+2$$

.
Apr 24, 2018
#2
+4286
+4

Ah, here it is!

The vertex has to be right in between them, so the vertex is $$(0, 2)$$. Now, we use the equation $$(x-h)^2=4p(y-k)$$$$p = -2$$ , because that is the directed distance between the vertex and focus. We get than $$x^2 = -8(y-2)$$, so

$$\boxed{y = -\frac{1}{8}x^2+2}$$ is the desired equation.

Apr 25, 2018
#3
+2448
+1

Thank you so much, but my teacher says it's $$y=- \frac{x^2}{8}+2$$

RainbowPanda  Apr 25, 2018
#4
+2448
+1

I believe this will work, ty ^-^

RainbowPanda  Apr 25, 2018
#5
+4286
+1

No problem,

CPhill, can I use your glasses?

tertre  Apr 25, 2018