2 taps A and B can fill a swimming pool in 3 hours. If turned on alone, it takes tap A 5 hours less than tap B to fill the same pool. How many hours does it take tap A to fill the pool?

Guest May 20, 2015

#1**+10 **

Let x be the time (in hours) that B takes to fill the pool.....then( x - 5) is the time it takes for A to fill the pool.

And every hour, B fills 1/x of the pool and A fills 1/(x -5) of the pool

And we know that :

Rate per hour x time = amount of job done....so.......

[(1/x) * 3] + [1/(x -5) * 3] = 1

3/x + 3/(x -5) = 1

[ 3(x - 5) + 3(x)] = x(x - 5)

[6x - 15 ] = x^2 - 5x simplify

x^2 - 11x + 15 = 0 and using the onsite solver, we have

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{11}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{61}}}}{\mathtt{\,-\,}}{\mathtt{11}}\right)}{{\mathtt{2}}}}\\

{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{61}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{11}}\right)}{{\mathtt{2}}}}\\

\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{1.594\: \!875\: \!162\: \!046\: \!672\: \!8}}\\

{\mathtt{x}} = {\mathtt{9.405\: \!124\: \!837\: \!953\: \!327\: \!2}}\\

\end{array} \right\}$$

Reject 1.59......so A takes about (x - 5)= (9.405 - 5) = 4.405 hours to fill the pool working alone

Check.... (3/9.405) + (3/4.405) ≈ 1

CPhill
May 20, 2015

#1**+10 **

Best Answer

Let x be the time (in hours) that B takes to fill the pool.....then( x - 5) is the time it takes for A to fill the pool.

And every hour, B fills 1/x of the pool and A fills 1/(x -5) of the pool

And we know that :

Rate per hour x time = amount of job done....so.......

[(1/x) * 3] + [1/(x -5) * 3] = 1

3/x + 3/(x -5) = 1

[ 3(x - 5) + 3(x)] = x(x - 5)

[6x - 15 ] = x^2 - 5x simplify

x^2 - 11x + 15 = 0 and using the onsite solver, we have

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{11}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{61}}}}{\mathtt{\,-\,}}{\mathtt{11}}\right)}{{\mathtt{2}}}}\\

{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{61}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{11}}\right)}{{\mathtt{2}}}}\\

\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{1.594\: \!875\: \!162\: \!046\: \!672\: \!8}}\\

{\mathtt{x}} = {\mathtt{9.405\: \!124\: \!837\: \!953\: \!327\: \!2}}\\

\end{array} \right\}$$

Reject 1.59......so A takes about (x - 5)= (9.405 - 5) = 4.405 hours to fill the pool working alone

Check.... (3/9.405) + (3/4.405) ≈ 1

CPhill
May 20, 2015

#2**+5 **

2 taps A and B can fill a swimming pool in 3 hours. If turned on alone, it takes tap A 5 hours less than tap B to fill the same pool. How many hours does it take tap A to fill the pool?

A is the fast one: let tap A take X hours to fill the pool

A fills 1 pool in X hours

that is 3 pools in 3X hours OR 3/X pools in 3 hours

B fills 1 pool in X+5 hours

that is 3 pools in 3(X+5) hours OR 3/(X+5) pools in 3 hours

So together in 3 hours they will fill

$$\frac{3}{X}+\frac{3}{X+5} \;\;pools\\\\

=\frac{3(X+5)+3X}{X(X+5)}\;\;pools\; in\; 3 \;hours\\\\

$But in 3 hours they fill 1 pool so $\\\\

\frac{3(X+5)+3X}{X(X+5)}=1\\\\

3(X+5)+3X=X(X+5)\\\\

3X+15+3X=X^2+5X\\\\

6X+15=X^2+5X\\\\

X^2+5X-6X-15=0\\\\

X^2-X-15=0\\\$$

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{15}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{61}}}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\

{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{61}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\

\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{3.405\: \!124\: \!837\: \!953\: \!327\: \!2}}\\

{\mathtt{x}} = {\mathtt{4.405\: \!124\: \!837\: \!953\: \!327\: \!2}}\\

\end{array} \right\}$$

Obviously the negative answer is invalid so X = 4.4051 hours to fill the pool

$${\mathtt{60}}{\mathtt{\,\times\,}}{\mathtt{0.405\: \!1}} = {\mathtt{24.306}}$$

So that is near enough to 4 hours and 24 minutes

**A will take 4 hours and 24 minutes to fill the pool **

**and **

**B will take 9 hours and 24 minutes to fill the pool.**

Melody
May 20, 2015

#3**0 **

Did you struggle with that one for as long as I did Chris?

I have done heaps of these but they turn into a saga EVERY time. LOL

Oh well I got there in the end, CPhill and I did it a bit differently but we both got the same answer.

That is always a good sign

Melody
May 20, 2015