+129850 See the following image :
Triangle AJB represents the cross-section of the cone
It's volume is (1/3)(pi)(5^2)(12) = 100 pi cm^3
We are trying to find a similar cross-section that will include all the points inside the cone that will be at least 1cm from the surface area of the cone....call this similar cross-section KGH
We need to find point "H".....this will have to be 1 unit from the cross-section diameter JB of the cone and 1 unit from the right side of the cone's cross-section which can be represented by the line y = (-12/5) ( x - 5)
In standard form the line is given by : 12x + 5y - 60 = 0
We know that the y coordinate of H = 1
So....using the formula for the distance from a point to a line, we can find the x coordinate of "H"....note that this x value must be < 5........so we have
l 12x + 5(1) - 60 l
_________________ = 1
sqrt ( 12^2 + 5^2 )
So we have that
12x - 55 = 13
12x = 68
x = 68/12 > 5.....so....no good
OR
12x - 55 = -13
12x = 42
x = 42/12 = 7/2 = 3.5 ......and this is what we need....this = the radius of the cross-section
So....we need to find a parallel line to y = 12x + 5y -60 and passing through "H" = (3.5, 1)
The side of our cross-section will lie on this line
So....the equation of this line will be
y = (-12/5)(x - 3.5) + 1
And letting x = 0....we can find the y coordinate of "G" = the distance from G to JB
So...we have.....
y = (-12/5) (-3.5) + 1
y = 9.4= the distance from G to JB
However....we need to subtract 1 from this value because we actually want the distance that G is from KH
So...the height of the cross-section = 8.4
So....the radius of this cross-section = 3.5 and it's height = 8.4
So.....rotating this about the y axis produces the volume of the cross-section =
pi (3.5)^2 (8.4) / 3 = 34.3 pi cm^3
And the ratio of the volume of the cross-section to the total volume of the cone is
34.3 pi 34.3
______ = _____ = .343
100 pi 100
Answer: 0.343
