L + L + 5 + 2L =36...........................(1)
L + L + 5 + 2[L + 5]=36....................(2)
From (1) above:
L =31/4 =7.75 - inches - the shortest piece
7.75 + 5 =12.75 - inches-the 2nd longest piece.
7.75 x 2 =15.5 - inches -the longest piece.
From (2) above:
L =21/4 =5.25 - inches - the shortest piece
5.25 + 5=10.25 - inches - the 2nd longest piece
10.25 x 2=20.50 - inches- the longest piece
15.50 + 20.50 =36 - inches - the sum of the longest pieces.
what is your reason for farming all the methods to solving these questions?
actively collecting, as if you intend on publishing some sort of study guide to these problems.
Oh, no. These are just questions that I don't have the solutions to and I can't figure out how to do them. I have attempted them already, but I keep getting the wrong answer. It's not like I'm cheating or something. I just need some help.
Case 1: 1st rope: x, 2nd rope: x+5, and the third rope 2x.
So, 4x+5=36, 4x=31, x=7.75 and 7.75*2=15.5 inches
Case 2: 1st rope: x, 2nd rope: x+5, and the third rope 2x+10.
So, 4x+15=36, 4x=21, x=21/4=5.35, and 2(10.25)=20.5 inches.
Case 3: x, 2x, 2x+5, and we have 5x+5=36, 5x=41, x=8.2 and 2(8.2)=16.4+5=21.4.
Case 4 There are other cases, maybe 2x, 4x, 4x+5 gives 10x+5=36, x=3.1 and 4(3.1)+5=17.4
This is 74.8 and there is another 16?
How about 2x, 2x+5, and 4x. 15.5?
The longest peice could be 15.5, 20.5, 17.4, 16.4, or 21 added together this is exactly 90.8 inches
So there are 5 different possibilies on how the rope is cut. (only lenghths are important, not the order thay are cut in)
Rather than spoil everyone's fun I will let you individually work out what these 5 double cuts are.
Hint: Let one peice be a and another a+5. You have to work out the other one. (5 possibilities.)
there are only 5 cases, of course they all total to 36
1) a, a+5, twice as big as the first one
2) a, a+5, half as big as the first one
3) a, a+5, twice as big as the second one
4) a, a+5, half as big as the second one one
5) a, a+5 =2a, 36-3a