Yes that is correct but most calculators can't do log base 24.
$$24^y=50\\\\
log 24^y=log50\\\\
ylog24=log50\\\\
y=\frac{log50}{log24}$$
This log can be any base so long as they are both the same base.
most calcs only do base 10 or base e
Either of these are fine :)
Using the change of base law your answer can be changed very easily as well
$$log_{b}(a)=\frac{log_n(a)}{log_n(b)}$$
it is $${{log}}_{{\mathtt{24}}}{\left({\mathtt{50}}\right)}$$ so it is 1.230949
Yes that is correct but most calculators can't do log base 24.
$$24^y=50\\\\
log 24^y=log50\\\\
ylog24=log50\\\\
y=\frac{log50}{log24}$$
This log can be any base so long as they are both the same base.
most calcs only do base 10 or base e
Either of these are fine :)
Using the change of base law your answer can be changed very easily as well
$$log_{b}(a)=\frac{log_n(a)}{log_n(b)}$$