256^(x+2)=16^(3x-1) How do I solve this equation for x? Help is appreciated. Thank You

256^(x+2)=16^(3x-1)

Notice that 256 =  2^8   and 16 = 2^4

So we have

2^8^(x + 2) = 2^4^(3x -1)   and dropping the equal bases and solving for the exponents, we have

8(x + 2) = 4(3x - 1)

8x + 16 = 12x - 4    add 4 to both sides and subtract 8x from both sides

20 = 4x    divide both sides by 4

5 = x

Thanks!!!!