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256^(x+2)=16^(3x-1) How do I solve this equation for x? Help is appreciated. Thank You

Guest Feb 10, 2015

Best Answer 

 #1
avatar+85819 
+10

256^(x+2)=16^(3x-1)

Notice that 256 =  2^8   and 16 = 2^4

So we have

2^8^(x + 2) = 2^4^(3x -1)   and dropping the equal bases and solving for the exponents, we have

8(x + 2) = 4(3x - 1)

8x + 16 = 12x - 4    add 4 to both sides and subtract 8x from both sides

20 = 4x    divide both sides by 4

5 = x

 

CPhill  Feb 10, 2015
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2+0 Answers

 #1
avatar+85819 
+10
Best Answer

256^(x+2)=16^(3x-1)

Notice that 256 =  2^8   and 16 = 2^4

So we have

2^8^(x + 2) = 2^4^(3x -1)   and dropping the equal bases and solving for the exponents, we have

8(x + 2) = 4(3x - 1)

8x + 16 = 12x - 4    add 4 to both sides and subtract 8x from both sides

20 = 4x    divide both sides by 4

5 = x

 

CPhill  Feb 10, 2015
 #2
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0

Thanks!!!!

Guest Feb 10, 2015

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