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297,49*(e^(-t/69,44) -140.83=0) i wanna no how much the t is i think round 50

 Feb 11, 2017
 #1
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Solve for t over the real numbers:
297.49 e^(-0.0144009 t) - 140.83 = 0

297.49 e^(-0.0144009 t) - 140.83 = 29749/100 e^(-(25 t)/1736) - 14083/100:
29749/100 e^(-(25 t)/1736) - 14083/100 = 0

Bring 29749/100 e^(-(25 t)/1736) - 14083/100 together using the common denominator 100 e^(25 t/1736):
-1/100 e^(-25 t/1736) (14083 e^((25 t)/1736) - 29749) = 0

Multiply both sides by -100:
e^(-25 t/1736) (14083 e^((25 t)/1736) - 29749) = 0

Split into two equations:
e^(-25 t/1736) = 0 or 14083 e^((25 t)/1736) - 29749 = 0

e^(-25 t/1736) = 0 has no solution since for all z element R, e^z>0:
14083 e^((25 t)/1736) - 29749 = 0

Add 29749 to both sides:
14083 e^(25 t/1736) = 29749

Divide both sides by 14083:
e^(25 t/1736) = 29749/14083

Take the natural logarithm of both sides:
(25 t)/1736 = log(29749/14083)

Multiply both sides by 1736/25:
Answer: |t = 1736/25 log(29749/14083)= 51.92911533539

 Feb 11, 2017
 #2
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Thank you very much!! i come to different answers it is for Analytical met viscous friction. i see how you do it thank you

 Feb 12, 2017

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