2ln10+log20/log121-ln11 equals -18.743, why and how?
I was given this problem for homework but whenever I enter it into my calculator I get something completely different. What am I doing wrong?
+118608 2ln10+log20/log121-ln11 equals -18.743, why and how?
$${\mathtt{2}}{\mathtt{\,\times\,}}{ln}{\left({\mathtt{10}}\right)}{\mathtt{\,\small\textbf+\,}}{\frac{{log}_{10}\left({\mathtt{20}}\right)}{{log}_{10}\left({\mathtt{121}}\right)}}{\mathtt{\,-\,}}{ln}{\left({\mathtt{11}}\right)} = {\mathtt{2.831\: \!933\: \!610\: \!243\: \!228\: \!5}}$$
It is because division is done before addition and subtraction Remember PEDMAS 
To do it on the calc you need to put more brackets in, then it gives you the answer that you seek :))
( 2ln10+log20 ) / ( log121-ln11 )
$${\frac{\left({\mathtt{2}}{\mathtt{\,\times\,}}{ln}{\left({\mathtt{10}}\right)}{\mathtt{\,\small\textbf+\,}}{log}_{10}\left({\mathtt{20}}\right)\right)}{\left({log}_{10}\left({\mathtt{121}}\right){\mathtt{\,-\,}}{ln}{\left({\mathtt{11}}\right)}\right)}} = -{\mathtt{18.743\: \!302\: \!368\: \!896\: \!347\: \!2}}$$
