3,2x^3,2 = 0,9x^0,9 please help!!

3.2x^3.2 = .9x^.9     divide both sides by 3.2

x^3.2 = (.9/3.2) x^.9  divide both sides by x^.9

x^3.2-.9 = (.9/3.2)

x^2.3 =   (.9/3.2)   take the log of both sides

log x^2.3 = log(.9/3.2)      and by a log property, we can write

2.3 log x  = log (.9/3.2)   divide both sides by 2.3

log x   =  [log(.9/3.2)]/2.3   and in exponential form, we can write

10 ^{[log(.9/3.2)]/2.3} = x  = about .576