3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]} I have no idea what this is or how to solve it.

Guest Jul 9, 2015

#1**+5 **

3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]}

$$\\=3 \times \{(300 - 80 \div 5) - [3 \times 25 - (8 - 2 \times 3)]\}\\\\

$Do the stuff in the brackets, and use PEDMAS $\\

$Multiplication and division is done before addition and subtraction$\\\\

=3 \times \{(300 - 16) - [3 \times 25 - (8 - 6)]\}\\\\

=3 \times \{(284) - [3 \times 25 - (2)]\}\\\\

=3 \times \{284 - [3 \times 25 - 2]\}\\\\

=3 \times \{284 - [75 - 2]\}\\\\

=3 \times \{284 - [73]\}\\\\

=3 \times \{284 - 73\}\\\\

=3 \times \{211\}\\\\

=3 \times 211\\\\

=633$$

Melody Jul 9, 2015

#1**+5 **

Best Answer

3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]}

$$\\=3 \times \{(300 - 80 \div 5) - [3 \times 25 - (8 - 2 \times 3)]\}\\\\

$Do the stuff in the brackets, and use PEDMAS $\\

$Multiplication and division is done before addition and subtraction$\\\\

=3 \times \{(300 - 16) - [3 \times 25 - (8 - 6)]\}\\\\

=3 \times \{(284) - [3 \times 25 - (2)]\}\\\\

=3 \times \{284 - [3 \times 25 - 2]\}\\\\

=3 \times \{284 - [75 - 2]\}\\\\

=3 \times \{284 - [73]\}\\\\

=3 \times \{284 - 73\}\\\\

=3 \times \{211\}\\\\

=3 \times 211\\\\

=633$$

Melody Jul 9, 2015