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3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]} I have no idea what this is or how to solve it.

 Jul 9, 2015

Best Answer 

 #1
avatar+109813 
+5

3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]} 

 

$$\\=3 \times \{(300 - 80 \div 5) - [3 \times 25 - (8 - 2 \times 3)]\}\\\\
$Do the stuff in the brackets, and use PEDMAS $\\
$Multiplication and division is done before addition and subtraction$\\\\
=3 \times \{(300 - 16) - [3 \times 25 - (8 - 6)]\}\\\\
=3 \times \{(284) - [3 \times 25 - (2)]\}\\\\
=3 \times \{284 - [3 \times 25 - 2]\}\\\\
=3 \times \{284 - [75 - 2]\}\\\\
=3 \times \{284 - [73]\}\\\\
=3 \times \{284 - 73\}\\\\
=3 \times \{211\}\\\\
=3 \times 211\\\\
=633$$
 

 Jul 9, 2015
 #1
avatar+109813 
+5
Best Answer

3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]} 

 

$$\\=3 \times \{(300 - 80 \div 5) - [3 \times 25 - (8 - 2 \times 3)]\}\\\\
$Do the stuff in the brackets, and use PEDMAS $\\
$Multiplication and division is done before addition and subtraction$\\\\
=3 \times \{(300 - 16) - [3 \times 25 - (8 - 6)]\}\\\\
=3 \times \{(284) - [3 \times 25 - (2)]\}\\\\
=3 \times \{284 - [3 \times 25 - 2]\}\\\\
=3 \times \{284 - [75 - 2]\}\\\\
=3 \times \{284 - [73]\}\\\\
=3 \times \{284 - 73\}\\\\
=3 \times \{211\}\\\\
=3 \times 211\\\\
=633$$
 

Melody Jul 9, 2015

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