+0

# 3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]} I have no idea what this is or how to solve it.

0
789
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3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]} I have no idea what this is or how to solve it.

Jul 9, 2015

#1
+109813
+5

3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]}

$$\\=3 \times \{(300 - 80 \div 5) - [3 \times 25 - (8 - 2 \times 3)]\}\\\\ Do the stuff in the brackets, and use PEDMAS \\ Multiplication and division is done before addition and subtraction\\\\ =3 \times \{(300 - 16) - [3 \times 25 - (8 - 6)]\}\\\\ =3 \times \{(284) - [3 \times 25 - (2)]\}\\\\ =3 \times \{284 - [3 \times 25 - 2]\}\\\\ =3 \times \{284 - [75 - 2]\}\\\\ =3 \times \{284 - [73]\}\\\\ =3 \times \{284 - 73\}\\\\ =3 \times \{211\}\\\\ =3 \times 211\\\\ =633$$

Jul 9, 2015

#1
+109813
+5

3 · {(300 - 80 ÷ 5) - [3 · 25 - (8 - 2 · 3)]}

$$\\=3 \times \{(300 - 80 \div 5) - [3 \times 25 - (8 - 2 \times 3)]\}\\\\ Do the stuff in the brackets, and use PEDMAS \\ Multiplication and division is done before addition and subtraction\\\\ =3 \times \{(300 - 16) - [3 \times 25 - (8 - 6)]\}\\\\ =3 \times \{(284) - [3 \times 25 - (2)]\}\\\\ =3 \times \{284 - [3 \times 25 - 2]\}\\\\ =3 \times \{284 - [75 - 2]\}\\\\ =3 \times \{284 - [73]\}\\\\ =3 \times \{284 - 73\}\\\\ =3 \times \{211\}\\\\ =3 \times 211\\\\ =633$$

Melody Jul 9, 2015