I'm assuming this is
3^352^(log10^(3^(1/4))
3^(1/4) = 1.3160740129524925 ... so we have
3^352^log10^1.3160740129524925 =
3^352^1.3160740129524925 =
3^463.25805255927736
In terms of base 10 .... 3 = 0.4771212547196624
So, we have
(10^0.4771212547196624)^463.25805255927736 =
10^221.030263296069725261145127163264 =
10^221 * 10^0.030263296069725261145127163264 =
10^221 * 1.072 {approximately }
Or, in scientifiic notation
1.072 x 10^221 = 1072 followed by 218 zeroes..... (more or less)
I'm assuming this is
3^352^(log10^(3^(1/4))
3^(1/4) = 1.3160740129524925 ... so we have
3^352^log10^1.3160740129524925 =
3^352^1.3160740129524925 =
3^463.25805255927736
In terms of base 10 .... 3 = 0.4771212547196624
So, we have
(10^0.4771212547196624)^463.25805255927736 =
10^221.030263296069725261145127163264 =
10^221 * 10^0.030263296069725261145127163264 =
10^221 * 1.072 {approximately }
Or, in scientifiic notation
1.072 x 10^221 = 1072 followed by 218 zeroes..... (more or less)
3^352^log(10^(sqrt(sqrt3(
\\y=3^{{352}^{log\left(10^\sqrt{\sqrt{3}}}\right)}}\\\\ y=3^{{352}^{log\left(10^{3^{0.25}}}}\right)}}\\\\ y=3^{{352}^{\left(3^{0.25}log10}\right)}}\\\\ y=3^{{352}^{\left(3^{0.25}}\right)}}\\\\ log(y)=log\left(3^{{352}^{\left(3^{0.25}}\right)}}\right)\\\\ log(y)={352}^{(3^{0.25})}log(3)\\\\ log(y)=1071.685578\\\\ y\approx 10^{1071.7}\\\\
This answer is different from Chris's and these large powers really confuse me.
Could other mathematicians (including Chris) take a look and comment please.
-----------------------------------------