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1) What is the exponential form of the logarithmic equation? 4=log0.8 04096

2) Solve the logarithmic equation. y=log5125

3) What are the x and y intercepts of the equation? y=log(3x+4)+2 Round the answers to the nearest hundredth.

 

Thank you :)

 Nov 20, 2018
 #1
avatar+105238 
+2

1) Exponential form is :

 

 0.8^4   = 0.4096

 

2) This says that     5^y  = 125   

Note 125   = 5^3

So.... 5^y = 5^3      implies that y = 3

 

3) y = log (3x + 4) +2

 

To find the y intercept, set x = 0   and we have

y = log (3(0) + 4) + 2

y =  log(4) + 2  ≈  2.60

 

 

To find the x intercept, set y = 0   and we have

0 =log (3x + 4)  + 2       subtract 2 from both sides

-2 = log (3x + 4)

 

In exponential form, we have

10^(-2)  = 3x + 4        subtract 4 from both sides

10^(-2) - 4  = 3x         divide both sides by 3

[ 10^(-2) - 4 ] / 3  = x  =  -1.33

 

 

cool cool cool

 Nov 20, 2018
edited by CPhill  Nov 20, 2018
 #2
avatar+300 
+1

Thanks dude! You're always so much better at explaining this stuff than my math teachers

Johnnyboy  Nov 20, 2018
 #3
avatar+105238 
+1

Well....I do what I can.....THX!!!!

 

 

cool cool cool

CPhill  Nov 20, 2018

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