+88 3 cards are chosen at random from a standard 52-card deck. What is the probability that they form a pair? (A 3-card hand is a 'pair' if two of the cards match in rank but the third card is different. For example, 668 is a pair, but 999 is not.)
THANKS FOR ALL HELP
ps the answer is not 48/425
+128408 I think this might be correct....but....I'd like someone else to check since I'm not great at these "counting" problems!!!
We have 13 ranks and we want to choose any 2 of 4 cards in one of them.....so.....number of possible pairs =
13 * 4C2
And...from any of the remaining 12 ranks, we want to choose any 1 of 4 cards from one of them =
12* 4C1
And the number of possible hands = 52C3
So..the probability is
[13 * 4C2] * [ 12 * 4C1] / 52C3 = 72 /425
